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<text style="letter-spacing:0px;block-progression:tb;text-indent:0;word-spacing:0px;color:#000000;text-transform:none" xml:space="preserve" line-height="125%" y="687.75928" x="153.25862"><tspan y="687.75928" x="153.25862" font-size="14px">delta</tspan></text>
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<text style="letter-spacing:0px;block-progression:tb;text-indent:0;word-spacing:0px;color:#000000;text-transform:none" xml:space="preserve" line-height="125%" y="738.10455" x="180.68153"><tspan y="738.10455" x="180.68153" font-size="14px">a</tspan></text>
<text style="letter-spacing:0px;block-progression:tb;text-indent:0;word-spacing:0px;color:#000000;text-transform:none" xml:space="preserve" line-height="125%" y="628.76648" x="190.6815"><tspan y="628.76648" x="190.6815" font-size="14px">b</tspan></text>
<text style="letter-spacing:0px;block-progression:tb;text-indent:0;word-spacing:0px;color:#000000;text-transform:none" xml:space="preserve" line-height="125%" y="534.92474" x="186.17192"><tspan y="534.92474" x="186.17192" font-size="14px">e</tspan></text>
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<text style="letter-spacing:0px;block-progression:tb;text-indent:0;word-spacing:0px;color:#000000;text-transform:none" xml:space="preserve" font-size="14px" line-height="125%" y="491.55411" x="434.41095"><tspan y="491.55411" x="434.41095">To square a join at exactly delta offset, such</tspan><tspan y="509.05411" x="434.41095">that (b) is delta distance from (a), and given</tspan><tspan y="526.55414" x="434.41095">that (c) is a perpendicular offset of (a) which</tspan><tspan y="544.05414" x="434.41095">is easily derived ... we need to calculate the</tspan><tspan y="561.55414" x="434.41095">distance (d) is from (c).</tspan><tspan y="579.05414" x="434.41095">Ø = pi - ß</tspan><tspan y="596.55408" x="434.41095">angle(bed) = Ø/2</tspan><tspan y="614.05408" x="434.41095">angle(bde) = pi/2 - Ø/2</tspan><tspan y="631.55408" x="434.41095">since trig. function ... cos = adjacent / hypot. </tspan><tspan y="649.05408" x="434.41095">cos(dac) = delta/length(ad), and ...</tspan><tspan y="666.55408" x="434.41095">cos(bad) = delta/length(ad)</tspan><tspan y="684.05408" x="434.41095">then angle(bda) = angle(cda)</tspan><tspan y="701.55408" x="434.41095">angle(bdc) = pi - (pi/2 - Ø/2) = pi/2 + Ø/2</tspan><tspan y="719.05408" x="434.41095">angle(adc) = pi/4 + Ø/4</tspan><tspan y="736.55408" x="434.41095">angle(dac) = pi/2 - (pi/4 + Ø/4) = pi/4 - Ø/4</tspan><tspan y="754.05408" x="434.41095">tan(dac) = tan(pi/4 - Ø/4) = length(cd)/delta</tspan><tspan y="771.55408" x="434.41095">length(cd) = delta * tan((pi - Ø)/4)</tspan><tspan y="789.05408" x="434.41095">since ... pi - Ø = ß ...</tspan><tspan y="797.00244" x="434.41095" font-size="4px" font-weight="bold"> </tspan><tspan y="811.55408" x="434.41095" font-weight="bold">length(cd) = delta * tan(ß/4)</tspan></text>
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